1.5x^2+3x+1.5=2450

Solution for 1.5x^2+3x+1.5=2450 equation:

1.5x^2+3x+1.5=2450

We move all terms to the left:

1.5x^2+3x+1.5-(2450)=0

We add all the numbers together, and all the variables

1.5x^2+3x-2448.5=0

a = 1.5; b = 3; c = -2448.5;
Δ = b2-4ac
Δ = 32-4·1.5·(-2448.5)
Δ = 14700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14700}=\sqrt{4900*3}=\sqrt{4900}*\sqrt{3}=70\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-70\sqrt{3}}{2*1.5}=\frac{-3-70\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+70\sqrt{3}}{2*1.5}=\frac{-3+70\sqrt{3}}{3}
$